the path of least resistance for the current would be down one connected bolt, then around the top plate, and up the other battery connected bolt, never down the pole, so the ceiling/floor gets heated up, possibly burn
note: those bolts must be supper long to go from ceiling to floor
still can spin a big truck and/or turn on incandescent bulbs with temperatures in the thousands of degrees
the internal resistance of lead-acid batteries is in the tens of mili-Ω, the circuit of 2 cables, 2 bolts and one plate/top of the pole would be in the low 100s mili-Ω. lets round up to 200mΩ, power = V•I = V^2/R = 12^2/0.2 = 720W, enough to heat up the top assembly of the pole, and smolder some wood
Please do. I don’t know what’s wrong with it
Edit: thanks folks! I feel like an idiot because that’s super obvious. :-)
the path of least resistance for the current would be down one connected bolt, then around the top plate, and up the other battery connected bolt, never down the pole, so the ceiling/floor gets heated up, possibly burn
note: those bolts must be supper long to go from ceiling to floor
12v is hardly anything. This is not a joke, go put your hands on both terminals of a car battery. You won’t feel a thing.
12 V is not enough to pass through unbroken skin, yes. But 12V has plenty to pass through some bolts and heat up enough to burn your house down.
You may be interested in StyroPyro’s video where he wired 100 car batteries in parallel. Still 12V, but huge current capacity.
still can spin a big truck and/or turn on incandescent bulbs with temperatures in the thousands of degrees
the internal resistance of lead-acid batteries is in the tens of mili-Ω, the circuit of 2 cables, 2 bolts and one plate/top of the pole would be in the low 100s mili-Ω. lets round up to 200mΩ, power = V•I = V^2/R = 12^2/0.2 = 720W, enough to heat up the top assembly of the pole, and smolder some wood